WEBVTT

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Hi. Let's take a look at an interesting property of right triangles.  

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Suppose we draw a right triangle, and we label the sides a, b, and c. 

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The side c, which is the side opposite the right angle, is called the hypotenuse.  

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That's h-y-p-o-t-e-n-u-s-e.

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Now, in terms of the angle theta, which I will select this angle and call it theta,

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then the side b is the side opposite the angle theta,

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and the side a is the side next to, or adjacent, the angle theta.

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Now let's take a look at the ratios of the sides of the right triangle.

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Let's pick, for example, the ratio of the length of side b to the length of side a.

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We could write that as b divided by a. Now, here's the interesting property.

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If we extend this side and we extend this side (even if it goes through the words)

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and then we close out the right triangle, we see something interesting.

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We can call this side right here b prime, and then we call this new side here a prime,

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and here's the part that's really interesting. 

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The ratio of b prime to a prime is the same as the ratio of b to a.

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So what that means is that the ratio of the sides of the triangle depend only 

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on the specific angle theta that is selected, as long as you're working in a right triangle.  

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So in trigonometry, the ratios of all the pairs of sides are given special names.  

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There are six of them. Let's go through them and define them in terms of the sides

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of the triangle. The first one is called the sine, and it's spelled s-i-n-e.  

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It's abbreviated s-i-n, and the way it works is this. The sine of theta is the value 

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given to the ratio of the opposite side divided by the hypotenuse,

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and we'll just abbreviate here, opposite divided by hypotenuse.  

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The next function we're going to look at is the cosine function. It is abbreviated

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c-o-s, and so the cosine of theta is the ratio of the adjacent side to the hypotenuse.

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The next one is called the tangent. It is abbreviated t-a-n, and the tangent of theta

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is the ratio of the opposite side to the adjacent side.  

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Alright, that's half of them. There are three more.  

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The next one is called the cosecant, c-o-s-e-c-a-n-t, abbreviated c-s-c,

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 and the cosecant of theta is the ratio of the hypotenuse to the opposite side.

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The next one is called the secant. It is abbreviated s-e-c, and the secant of theta

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is the ratio of the hypotenuse to the adjacent side.  

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And then the last one is the cotangent, abbreviated c-o-t, and it is the ratio of 

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the adjacent side to the opposite side.  

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These six ratios and their associated names in terms of angle theta

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are called the right triangle definitions of the trig functions of theta.

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You need to study these carefully. You need to practice writing them over and over

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again until you're absolutely comfortable with them.  

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Now let's take a look at an example of how this is used.

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Use the definitions to find the trig functions for the given triangle.  

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Alright, so what do we have? We have a right triangle.  

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We have a designated angle, theta, and we know that the side 

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opposite theta is 2 units long and the side adjacent to theta is 5 units long.

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So, what's missing? Well, of course, what's missing is the hypotenuse, 

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this side right here. We know this is a right triangle, so let's find the hypotenuse.  

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We want to know the length of side c. Alright now what's the relationship?  

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Think about it. 

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What does the Pythagorean theorem say about the relationships of the 3 sides?

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Right. It is c squared equals a squared plus b squared. We're looking for side c.

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So we're going to write c squared is, a is 5, so that's 5 squared, and b is 2, 

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so that's 2 squared, so c squared is 25 plus 4 which is 29. Now, 

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this is an algebraic equation, and so when you take the square root of both sides

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algebraically, unrelated to geometry, you would get plus or minus the square root of 29.

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But because this is the length of the side of a triangle,

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there's a geometric restriction here which says of course the side of a triangle 

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can't be negative, and so in our case, c is the square root of 29.

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By the way, you will do this process many times in trigonometry. You may want to

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start trying to think of doing it mentally, and here's what you would do.  

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You're looking for the hypotenuse. You square this side, 25, this side, 4, 

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add them together, 29, square root of 29. So get used to practicing this mentally.  

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It will save you a lot of time. So back to the problem.  

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We need to use the definitions. Do you remember them?

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If not, get them out in front of you and then practice, so in the future 

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you will remember the six trig functions. OK, here we go. We start with sine.  

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The sine of theta is, say it to yourself, it is the opposite over the hypotenuse,

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so that's 2 over the square root of 29. OK, now we're going to stop for a second.  

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Unless you are specifically told to do so, there is no reason why you have to 

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rationalize this denominator. It is perfectly acceptable to leave this 

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unless you have instructions that tell you otherwise. The cosine of theta is

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adjacent over hypotenuse, so that's 5 over the square root of 29.

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And then the tangent of theta. OK say it to yourself. What is it?  

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It is the opposite over the adjacent, so it's 2 over 5.

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Alright, next 3. Cosecant of theta is the hypotenuse over the opposite, 

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square root of 29 over 2. Be careful when you write this here.  

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The 29 is under the radical. The division sign and the 2 are not. 

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Next is the secant of theta, and the secant of theta is the hypotenuse over the 

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adjacent. Correct. So it's the square root of 29 all over 5.  

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And the last one is cotangent, and the cotangent of theta is equal to

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the adjacent over the opposite, and so it is 5 over 2. 

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OK, this satisfies the directions, but let's look at what we have here.

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These are the six trig functions of theta for this triangle.  

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We calculated these using the definitions, but you have probably noticed at this point 

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that there are certain relationships between the six of these. 

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So the next thing we're going to do is we're going to take a look at a little bit

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faster way to get some of these by using the relationships between them.

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Alright, I have here on the board the definitions, the right triangle definitions,

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of the six trig functions. What we want to do is look at the relationships.  

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We're trying to see how these fit together and how one is related to the other.  

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Well first of all, I notice that sine divided by cosine, well what would it be?

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It would be this expression divided by this one, and if you simplified it, 

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hypotenuse and hypotenuse would cancel and you'd end up with 

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opposite over adjacent which is 

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tangent. Ok, so we notice that relationship, so we say that 

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the sine of theta divided by the cosine of theta is equal to the tangent of theta.

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Now let's look at these.

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What is the relationship between sine, cosine, and cotangent?

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Obviously there are lots of relationships, but there are some that seem to be used

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more often than others, so those are the ones we're going to point out here.

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What happens if you divide cosine by sine?  

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Well again hypotenuse cancels, but you get adjacent over opposite

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which is cotangent. So we're going to write down this one. 

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Cosine of theta divided by sine of theta equals cotangent of theta.  

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Alright, these two in particular are what are called the quotient identities,  

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and as I said, there are others, but these are the most used.

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Now let's take a look at the reciprocal identities.  

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Well, sine is opposite over hypotenuse. Cosecant is hypotenuse over opposite.

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So what that means is that cosecant of theta is equal to 1 over the sine of theta, 

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and for that matter, the sine of theta is equal to 1 over the cosecant of theta. 

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But once you've learned the identity one way, of course, you can simplify

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it to get the other one. What else do we see? 

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Well we see that the secant of theta is equal to 1 over, what? 

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Mmhm, cosine, and then, what about the cotangent? 

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The cotangent of theta is 1 over the tangent of theta, and these very descriptively 

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are called re-cip-ro-cal, reciprocal identities because that describes the relationship.

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OK, the next group of identities take a little bit more thought, but not that much. 

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What happens if you take the sine and you square it and the cosine and you square it? 

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Well it's not quite as obvious from these definitions, but if you're curious 

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about where this comes from, you can go back to a previous example that we did 

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and actually take those values we did with the triangle that had 

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the 2 and the 5 and the square root of 29 and you can square the values,

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and see what happens and I'll show you the result. 

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The result is that if you take the sine and you square it, so the sine of theta 

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squared, and you add it to the cosine squared of theta you will get 1.  

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Notice that this is really the same expression as the sine of theta squared. 

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It doesn't mean anything strange like square a number and multiply it by theta.  

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This is all one term raised to the second power, but this is how it's written.

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The next relationship that follows this pattern is that if you square the tangent 

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of theta and you add 1 you will get the value of the secant squared of theta,

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and the third one is that if you take the cotangent of theta and square it 

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and add 1 you will get the cosecant squared of theta. 

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These are called the Pythagorean identities. 

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Together this group, this whole group together, these are called 

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the fundamental identities. You need to practice these.

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You need to be very familiar with them. You need to be able to write them down.  

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You need to be able to recall them with barely any effort whatsoever.

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Now let's take a look at how this can be used. 

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Example 2:  Use identities to find the exact value of, 

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and we have two expressions.  Now down here at the bottom of the board 

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I have the fundamental identities that we developed in the last segment.  

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I'm going to just leave them here so that we can refer to them.

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So let's see what we have. We have the tangent of 75 minus, 

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and then we have the sine of 75 degrees divided by the cosine of 75 degrees.

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OK, so what's the identity that we can use here to simplify this?

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Well, sine of theta divided by cosine of theta is tangent of theta,

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and since these angles are the same, both 75 degrees, 

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we can rewrite this expression by copying over the first term, 

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making no changes, and then replacing the second expression with 

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the tangent of 75, and at this point it's pretty obvious that the exact value is 0.

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Alright, let's look at the second one. As soon as you see the 

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sine squared pi over 5 and then secant squared pi over 5, where are you going to go?

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Sure, you're going to go to these identities here. Now we have sine squared 

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and secant squared so that is a possibility of the first one or the second one.  

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Let's see. Which one has the most promise?  

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Well, we know that secant is related to what? Look around.  

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Secant is related to cosine. They're reciprocals, 

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and if I can change a secant expression to be defined in terms of cosine, 

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then I should be able to use this identity second.  

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Alright, so the first thing I'm going to do is copy the first term, and then 

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I'm going to rewrite the secant squared pi over 5. Let's see.  

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Secant and cosine are reciprocals, so if I have 1 over the secant squared 

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of an angle, I should be able to write it as the cosine squared of the same angle.  

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Now, this is actually the reverse of the identity that I have written here.  

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I'm actually using the cosine of theta is 1 over the secant of theta. But that's fine.

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Once you know this one you can get the other one. And then what do I have? 

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I have sine squared of an angle plus cosine squared of an angle is 1. 

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Alright, let's look at another example of how we use these identities.

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Example 3: Given that the sine of theta is 1/4 and that theta is an acute angle,

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find the exact value of the remaining five trig functions.

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Alright, so let's take a look at what we have. So we have a right triangle.  

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We know that because we are using trig functions, and of course, 

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they are trig functions of right triangles. So we have a right triangle.

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Let me just draw a little bitty one right here. Just enough to label the sides.  

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Here's angle theta, and the sine is 1 divided by 4. Think about the definition again.  

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So that means, 1, so that means this side is 1, and the hypotenuse is 4.  

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So what's missing is this side. Now remember how I told you to 

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learn how to do this mentally? Let's see if we can find this side mentally.  

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It would be c squared equals a squared plus b squared.

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So what that means is this side squared is that one squared minus that one squared.

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So what do we get? 

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We get 16 minus 1 which is 15, which means this side is the square root of 15 units. 

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16 minus 1 and then square root of both sides.

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OK, so what we have is opposite, adjacent, and hypotenuse.

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But, we have all of this. So, we start. The sine of theta is given.  

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Notice how every time I do this I write three down, three more down, in the same order. 

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It helps you to remember these things if you are very orderly and organized

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about how you do this. Now, the cosine of theta. It is going to be 

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adjacent over hypotenuse. Now, use the identities. What is tangent?  

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Tangent is cosine divided by sine, and the 4's will cancel, 

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and what you get is 1 over the square root of 15. Oops, let's look at that.  

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Tangent, I think I said cosine over sine. Ooo, no. Tangent is sine over cosine.  

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Alright, so the tangent of theta, let's look at it again, is sine divided by cosine. 

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And you do have to be careful when you do this because of course 

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it's the same words over and over again.  

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So it would be 1/4 divided by the square root of 15 fourths, the 4's cancel,

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and so what you do is write 1 over the square root of 15.  

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OK, now basically at this point you've got all of them because the next three are 

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reciprocals of each of these three. So as long as you are careful with what you write, 

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the cosecant of theta would be the reciprocal of 1/4 which is 4.  

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The secant of theta is the reciprocal of the cosine, 

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and the cotangent of theta is the reciprocal of the tangent. 

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Alright now, before you stop, you go back and you check all of this.  

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This was given, 

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cosine is this over this,

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tangent is that divided by that, from this identity. 

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Cosecant is the reciprocal of this one, 

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secant the reciprocal of this one,

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cotangent the reciprocal of this one, and you've got all six.

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Let's look at another property of right triangles.

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Let's discuss the relationship of cofunctions of complementary angles.

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Alright, from geometry you may remember that complementary angles

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are angles that have the sum of...  Do you remember?

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Yes, 90 degrees or pi over 2. So let's remember that the word

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complementary means that two angles have the sum of 90 degrees or pi over 2.

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So in this right triangle, we have the sides labelled a, b, c is the hypotenuse.

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This is the angle theta, right angle. So the question is, 

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what is this angle in terms of theta?

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Well, I gave it away a little bit when I talked about complementary angles

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because, if you remember, the sum of all three angles of a triangle is 180 degrees.

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So if it's a right triangle then that means that the sum of these two angles is,

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yes, 90 degrees which means these are complementary angles.  

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So what that means is that I can label this angle right here, 

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and I'm going to bring it out to here. I'm going to label that angle as what's left.  

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The sum is 90, so I could say theta plus this angle is 90. So what's left 

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for this one is 90 degrees minus what was used here,

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or I could write it as pi over 2 minus theta.

00:23:31.505 --> 00:23:37.004
Ok, now you have to get used to this notation so that when you see it you can spot it.

00:23:37.006 --> 00:23:43.023
So if this angle is theta, then the other acute angle in the right triangle could be

00:23:43.025 --> 00:23:48.526
written as 90 degrees minus theta, or it could be written as pi over 2 minus theta.

00:23:48.528 --> 00:23:54.531
Alright, now let's look at cofunctions of these complementary angles. 

00:23:54.533 --> 00:24:00.040
Lets start with theta. With theta, let's just take the first one.  

00:24:00.042 --> 00:24:06.292
So we'll say the sine of theta is... OK now remember the definition. 

00:24:06.294 --> 00:24:10.797
The sine of theta is the opposite over the hypotenuse so that's 

00:24:10.799 --> 00:24:16.057
the length of side b divided by the length of side c.  

00:24:16.059 --> 00:24:22.556
Alright now, what is the cofunction for sine? Think about the word co-sine. 

00:24:22.558 --> 00:24:30.320
The cofunction is the cosine. What is the value of the cosine?  

00:24:30.322 --> 00:24:34.074
But we're not going to take the cosine of theta. We're going to look at 

00:24:34.076 --> 00:24:39.831
the cofunction of the complementary angle, which is this one.

00:24:39.833 --> 00:24:44.835
Now, I can write it either way. I'm going to choose to write it as 

00:24:44.837 --> 00:24:50.085
pi over 2 minus theta, but I could have put 90 degrees minus theta.  

00:24:50.087 --> 00:24:56.096
And so what is the cosine of this angle?  

00:24:56.098 --> 00:25:03.844
Alright, now think. Cosine is adjacent over hypotenuse.  

00:25:03.846 --> 00:25:08.611
I'm using this angle, so this is the adjacent side.

00:25:08.613 --> 00:25:12.607
This is the opposite side. This is the adjacent side. 

00:25:12.609 --> 00:25:18.617
So the cosine of this angle is b over c.

00:25:18.619 --> 00:25:22.626
OK, well as soon as I get to this point, what do you realize?

00:25:22.628 --> 00:25:38.377
You realize that cofunctions of complementary angles are equal.

00:25:38.379 --> 00:25:46.875
So what we have is this. We have that the sine of theta is equal to 

00:25:46.877 --> 00:25:55.153
the cofunction of the complementary angle. 

00:25:55.155 --> 00:25:58.657
Now, if we had all day we could go through all of the other trig functions, 

00:25:58.659 --> 00:26:04.407
but I think by this process you can see that I could write a similar situation for, 

00:26:04.409 --> 00:26:11.660
let's say, the tangent of theta, and I could write this as equal to 

00:26:11.662 --> 00:26:19.657
the cotangent of the complementary angle, and I could continue along 

00:26:19.659 --> 00:26:24.443
with secant and cosecant. So I could write that the secant of theta 

00:26:24.445 --> 00:26:37.449
is the cosecant of the complementary angle. 

00:26:37.451 --> 00:26:44.196
Alright, these and the rest of the relationships show you that 

00:26:44.198 --> 00:26:49.400
cofunctions of complementary angles are equal.

00:26:50.959 --> 00:26:53.462
Let's take a look at an example of how 

00:26:53.464 --> 00:26:57.713
the complementary angle theorem can be used to simplify an expression.

00:26:57.715 --> 00:27:00.473
OK, now you need to remember the fundamental identities, 

00:27:00.475 --> 00:27:05.226
and I have some of the cofunctions of complementary angles 

00:27:05.228 --> 00:27:08.975
identities still listed down here so we can refer to this.  

00:27:08.977 --> 00:27:13.732
Ok, a says the cosine of 40 degrees divided by the sine of 50 degrees. 

00:27:13.734 --> 00:27:18.741
OK, well it should jump out at you that the sum of 40 and 50 is 90, 

00:27:18.743 --> 00:27:23.989
and so these are complementary angles. So what that means is we can rewrite 

00:27:23.991 --> 00:27:30.250
this expression, let's go with the numerator, so the cosine of 40 degrees is equal to 

00:27:30.252 --> 00:27:37.747
the cofunction of the complementary angle. And that's because if this angle 

00:27:37.749 --> 00:27:44.752
is theta, then this angle is 90 degrees minus theta. And then we copy over the denominator,

00:27:44.754 --> 00:27:51.750
and immediately we see that what we have here is equal to 1. 

00:27:51.752 --> 00:27:57.280
Alright, let's look at b. One plus the tangent squared of 5 degrees 

00:27:57.282 --> 00:28:03.279
minus the cosecant squared of 85 degrees. OK, what hits you first?

00:28:03.281 --> 00:28:09.780
Well, maybe it's the fact that 5 degrees and 85 degrees are complementary angles.

00:28:09.782 --> 00:28:13.292
So we know somewhere we're going to use one of these.

00:28:13.294 --> 00:28:19.550
But we have tangent and cosecant, and none of this is going to be direct.

00:28:19.552 --> 00:28:23.800
So what we're going to have to do is find an identity, rewrite some of this, 

00:28:23.882 --> 00:28:30.300
then use one of these complementary angle expressions. 

00:28:30.302 --> 00:28:34.303
OK, there are a couple of ways you can go here. 

00:28:34.305 --> 00:28:40.459
I would think that the most efficient approach would be to recognize right away

00:28:40.551 --> 00:28:45.578
that this expression can be rewritten as what? 

00:28:45.580 --> 00:28:48.077
Now think about the Pythagorean identity.  

00:28:48.079 --> 00:28:53.582
Tangent squared of an angle plus 1 is equal to what?

00:28:53.584 --> 00:29:01.090
Go through them. You should remember that it is secant squared of this angle

00:29:01.092 --> 00:29:12.591
which is 5 degrees. Now I have minus cosecant squared of 85 degrees.

00:29:12.593 --> 00:29:24.115
Well, what can I do now? How can I write say this one in terms of 5 degrees?

00:29:24.117 --> 00:29:28.869
Well this is cosecant. I could change either one of them actually. I just chose to do

00:29:28.871 --> 00:29:37.369
this one. I could rewrite this as the secant squared of 5 degrees, and then I know 

00:29:37.371 --> 00:29:45.384
I've got it here because I've got the same two expressions. Subtract, and I get 0.

00:29:45.386 --> 00:29:49.888
Alright, let's take a look at another example.

00:29:51.146 --> 00:29:57.893
This time our angles are given in radian measure. c) We want to find 

00:29:57.895 --> 00:30:04.899
the exact value of the sine of 5 pi over 12 divided by the cosine of pi over 12.  

00:30:04.901 --> 00:30:10.914
Well, 5pi over 12 and pi over 12 are not special angles, so

00:30:10.916 --> 00:30:15.915
we're not going to be able to find the exact value exactly as the expression is written.

00:30:15.917 --> 00:30:21.913
So let's look at the two angles. I'm going to walk over here, and I'm going to 

00:30:21.915 --> 00:30:34.162
examine 5 pi over 12 and pi over 12. What if I added the two angles?

00:30:34.164 --> 00:30:42.915
Well, I would get 6 pi over 12 which is pi over 2.  

00:30:42.917 --> 00:30:47.950
So now what do we know about these two angles?

00:30:47.952 --> 00:30:53.699
They are complementary angles because the sum is pi over 2.

00:30:53.701 --> 00:30:58.708
What do we know about complementary angles? We know that cofunctions 

00:30:58.710 --> 00:31:03.964
of complementary angles are equal. So let's look. Here are some of the 

00:31:03.966 --> 00:31:12.465
cofunction identities. We can rewrite the sine of 5 pi over 12 as the 

00:31:12.467 --> 00:31:32.463
cosine of pi over 2 minus 5 pi over 12. And then I'll just copy the denominator over, 

00:31:32.465 --> 00:31:36.748
and because of what we did over here, we see that [the cosine of] pi over 2  

00:31:36.750 --> 00:31:47.496
minus 5 pi over 12 is the cosine of pi over 12. The denominator is the cosine 

00:31:47.498 --> 00:31:55.267
of pi over 12, and so the exact value of this expression is 1. 

00:31:55.269 --> 00:32:03.015
d) We want to find the exact value of the tangent of pi over 6 minus 

00:32:03.017 --> 00:32:10.017
the cotangent of pi over 3. So once again, let's look at the two angles.

00:32:10.019 --> 00:32:20.292
Pi over 6 plus pi over 3. Well we get a common denominator, so we write 

00:32:20.294 --> 00:32:29.049
this is pi over 6, copying it over, we write this as 2 pi over 6. We add these. 

00:32:29.051 --> 00:32:34.807
We get 3 pi over 6. We reduce, and we get pi over 2.  

00:32:34.809 --> 00:32:41.062
So what have we found out? We found out here that pi over 6 and pi over 3 are

00:32:41.064 --> 00:32:46.560
complementary angles because their sum is pi over 2. 

00:32:46.562 --> 00:32:57.564
So let's rewrite the tangent of pi over 6 using this second identity. It would be 

00:32:57.566 --> 00:33:15.308
the cotangent of pi over 2 minus pi over 6, and then I copy this part over.

00:33:15.310 --> 00:33:23.312
Now this, according to what we saw here, can be rewritten as the cotangent of 

00:33:23.314 --> 00:33:33.616
pi over 3. So what do we have here?  0.

00:33:33.618 --> 00:33:37.620
OK.  Now let's move on to another example.

00:33:38.402 --> 00:33:45.624
Example 5: Given the cosecant of theta is 6, find the exact value of these

00:33:45.626 --> 00:33:50.629
four expressions. OK, now what you want to do here is use the most efficient method. 

00:33:50.631 --> 00:33:56.381 
We have the definitions. We have the reciprocal, Pythagorean, and quotient identities.

00:33:56.383 --> 00:34:00.391
And then we have the cofunction of complementary angles relationships. 

00:34:00.393 --> 00:34:05.898
So we go for what's most efficient. Well, let's see. The cosecant and the sine 

00:34:05.900 --> 00:34:13.147
are related. They are reciprocals. This 6 is a whole number. It has a denominator of 1. 

00:34:13.149 --> 00:34:20.647
The reciprocal of that would be 1/6, so the sine of theta is 1/6.

00:34:20.649 --> 00:34:28.146
Alright, cotangent squared of theta. What do we know about cotangent squared 

00:34:28.148 --> 00:34:33.676
that has a direct relationship to cosecant? OK, well we know this identity.  

00:34:33.678 --> 00:34:42.175
We know that the cotangent squared of theta plus 1 is the cosecant squared of theta.

00:34:42.177 --> 00:34:49.187
We want to solve for cotangent squared, and that would be 

00:34:49.189 --> 00:34:55.446
cosecant squared of theta minus 1. Alright, well we've just about got it because 

00:34:55.448 --> 00:35:05.445
cosecant squared would be 6 squared, minus 1, so that would be 35.

00:35:05.447 --> 00:35:12.193
Alright, what about this one? Right away you should see that this angle, 

00:35:12.195 --> 00:35:23.448
in these parentheses, this angle is the complement of the angle theta.

00:35:23.450 --> 00:35:32.966
So I can rewrite this expression. The cofunction of secant would be cosecant. 

00:35:32.968 --> 00:35:37.958
And then the complement of this angle, this angle is 90 degrees minus theta, 

00:35:37.960 --> 00:35:43.991
the complement of this angle is theta, and so what's the cosecant of theta? 

00:35:43.993 --> 00:35:46.497
Given as 6.  

00:35:46.499 --> 00:35:53.745
Alright, part d. Secant squared of theta. Hmm. OK, well it's certainly 

00:35:53.747 --> 00:35:56.503
not going to have anything to do with cofunctions of complementary angles.  

00:35:56.505 --> 00:36:02.508
And in terms of identities, there is no identity that directly relates 

00:36:02.510 --> 00:36:08.016
secant or secant squared with cosecant. So I think at this point, 

00:36:08.018 --> 00:36:11.768
the most efficient thing to do is to draw a triangle, label the sides, and then just

00:36:11.770 --> 00:36:18.027
read directly off of the triangle. So let's draw a triangle. 

00:36:18.029 --> 00:36:22.783
It doesn't have to all be perfect here, but just enough to get the idea.  

00:36:22.785 --> 00:36:29.532
This is the cosecant, so this is going to be the hypotenuse over the opposite, 

00:36:29.534 --> 00:36:35.782
or you can read from the sine, opposite over hypotenuse. So this is 6, and this is 1.  

00:36:35.784 --> 00:36:45.528
The missing side is 36 minus 1 is 35, and then we take the square root.

00:36:45.530 --> 00:36:51.808
Ok, so there are the three sides. Now, the secant is, well think about what that is.

00:36:51.810 --> 00:36:58.318
It's going to be the hypotenuse over the adjacent. The way I actually remember this

00:36:58.320 --> 00:37:00.819
is I think of the fact that it's the reciprocal of the cosine.  

00:37:00.821 --> 00:37:04.323
Cosine is adjacent over hypotenuse, and then I take the reciprocal.

00:37:04.325 --> 00:37:09.568
OK, so what do I have here? And let's not forget that it is squared.  

00:37:09.570 --> 00:37:15.330
So let's set up for that before we read, and we want hypotenuse, which is 6, 

00:37:15.332 --> 00:37:32.853
over adjacent, which is square root of 35, and we square that so we get 36 over 35.

00:37:32.855 --> 00:37:36.857
So in summary, how do you find exact values? 

00:37:36.859 --> 00:37:39.087
You use everything you know about this.  

00:37:39.089 --> 00:37:43.089
You use the right triangle definitions of the trig functions when appropriate.  

00:37:43.091 --> 00:37:47.366
You use the complementary angle theorem when appropriate, and you also use 

00:37:47.368 --> 00:37:51.872
identities when that's the most efficient method. You need to study all of these 

00:37:51.874 --> 00:37:58.100
relationships and master them until you are perfectly comfortable using them.

00:38:00.000 --> 00:38:07.385
Computing Trig Functions of Acute Angles
Let's first talk about three acute angles.

00:38:07.387 --> 00:38:24.155
We call these special angles. Let's look at a 30 degree angle, which is pi over 6,

00:38:24.157 --> 00:38:34.915
a 45 degree angle, pi over 4, and then a 60 degree angle, pi over 3, 

00:38:34.917 --> 00:38:39.665
and let's talk about finding the trig functions of these angles.

00:38:39.667 --> 00:38:52.414
Let's take 45 degrees first. Let's draw a triangle, and we will choose this triangle

00:38:52.416 --> 00:39:00.915
to be a right triangle, but we want it to be written so that it is an isosceles triangle

00:39:00.917 --> 00:39:10.451
where these two sides have the same length. Now it really doesn't matter 

00:39:10.453 --> 00:39:14.204
what the length is of the two sides as long as they are the same.  

00:39:14.206 --> 00:39:22.215
Let's try to make this look a little more like they're the same.  

00:39:22.217 --> 00:39:28.472
So for convenience sake I will just say that the length of each side is 1.  

00:39:28.474 --> 00:39:33.220
So what is the hypotenuse? Alright, let's see if we know how to do this.  

00:39:33.222 --> 00:39:38.471
We're looking for c. So it's this squared, plus this side squared, 

00:39:38.473 --> 00:39:41.233
add them together, and then take the square root.

00:39:41.235 --> 00:39:45.486
So it's going to be 1 squared plus 1 squared is 1 plus 1 which is 2, 

00:39:45.488 --> 00:39:55.485
so this side is the square root of 2. Well, let's see. If this is an isosceles triangle, 

00:39:55.487 --> 00:40:01.501
then that means that this angle right here is 45 degrees, and of course, 

00:40:01.503 --> 00:40:06.006
that was by design because I want to study the trig functions of a 45 degree angle.  

00:40:06.008 --> 00:40:12.264
So let's see what we have. Well we know that the sine, 

00:40:12.266 --> 00:40:17.761
and of course this is pi over 4, and you want to think in radians as well as degrees.  

00:40:17.763 --> 00:40:25.005
So we say that the sine of 45 degrees is the opposite over hypotenuse,

00:40:25.007 --> 00:40:30.778
and again there is no need to rationalize unless you are specifically told to do so. 

00:40:30.780 --> 00:40:40.031
The cosine of 45 degrees is adjacent over hypotenuse, 

00:40:40.033 --> 00:40:51.804
and the tangent of 45 degrees is 1 over 1 which is 1.

00:40:51.806 --> 00:40:57.299
These are the first three trig functions. You can get the next three by taking the

00:40:57.301 --> 00:41:03.810
reciprocal of each one of these. So we will just leave that to be done when we need it.

00:41:03.812 --> 00:41:10.064
Now let's look at a 30 degree angle and a 60 degree angle at the same time.

00:41:10.066 --> 00:41:17.074
So we have a 30 degree angle, pi over 6, and we're also going to look at a 

00:41:17.076 --> 00:41:23.583
60 degree angle, and how are we going to do that? Well, we are going to draw 

00:41:23.585 --> 00:41:33.835
an equilateral triangle or some approximation of an equilateral triangle.  

00:41:33.835 --> 00:41:38.099
Now we have to be creative here. We know that if it's an equilateral triangle, 

00:41:38.101 --> 00:41:43.604
all three angles are 60 degrees. I want to represent 60 and 30 and read from there.  

00:41:43.606 --> 00:41:48.107
So what I'm going to do is, OK, I know this is 60 degrees.  

00:41:48.109 --> 00:41:57.608
I'm going to drop a perpendicular which bisects this side. That means that this angle 

00:41:57.610 --> 00:42:05.859
is 30 degrees, and what I'll do is I'll just say that the length of this side is 2, 

00:42:05.861 --> 00:42:13.361
making the length of this half of the same length, 1. That's very convenient.  

00:42:13.363 --> 00:42:16.107
Of course you could use any numbers, but whatever you do the ratio is that 

00:42:16.109 --> 00:42:20.642
this will be twice that side. OK what is the length of this side? 

00:42:20.644 --> 00:42:27.142
It's going to be 2 squared which is 4 minus 1 squared, so that's 4 minus 1 is 3. 

00:42:27.144 --> 00:42:32.145
So the length of this side will be the square root of 3.

00:42:32.147 --> 00:42:37.143
Reading from the triangle. Alright, let's do 30 first, which means I'm going to read

00:42:37.145 --> 00:42:46.417
this angle. So this side is opposite. This side is adjacent. OK, so I'm going to do 

00:42:46.419 --> 00:43:00.669
the sine of 30, and then I'm going to read the cosine of 30, and then the tangent of 30.

00:43:00.671 --> 00:43:11.190
Alright, the sine of 30 is opposite over hypotenuse. The cosine of 30 is 

00:43:11.192 --> 00:43:21.201
adjacent over hypotenuse. And the tangent of 30 is, and you can either read it

00:43:21.203 --> 00:43:24.456
from the triangle, or we've done enough of this now that we know that 

00:43:24.458 --> 00:43:29.210
it's going to 1 over the square root of 3 because we can use the identity, 

00:43:29.212 --> 00:43:33.211
the reciprocal (quotient) identity that the tangent is the sine over the cosine.  

00:43:33.213 --> 00:43:39.721
OK, we can get the other three using the reciprocal properties.

00:43:39.723 --> 00:43:46.224
Alright, now let's read the trig functions of the 60 degree angle. So we want 

00:43:46.226 --> 00:43:55.977
the sine of 60 or pi over 3, we want the cosine of 60, and the tangent of 60.  

00:43:55.979 --> 00:44:09.000
The sine is going to be opposite over hypotenuse, and then at this point 

00:44:09.002 --> 00:44:14.749
you might start to realize that cofunctions of complementary angles are equal 

00:44:14.751 --> 00:44:22.251
means that the cosine of 30 equals the sine of 60 and the sine of 30 degrees 

00:44:22.253 --> 00:44:28.018
is the cosine of 60 degrees. We don't necessarily have to read all of this.  

00:44:28.020 --> 00:44:34.772
And then the tangent of 60 is going to be the opposite over the adjacent 

00:44:34.774 --> 00:44:41.780
which is the square root of 3, or the reciprocal of, well let's not.  

00:44:41.782 --> 00:44:45.533
We're not going to have cotangent here. We're not going to write all those down.  

00:44:45.535 --> 00:44:51.535
You can figure those out using the reciprocal. OK, so what do we have here?  

00:44:51.537 --> 00:44:55.543
We have some things that would be very convenient to memorize.  

00:44:55.545 --> 00:45:00.295
So what we want to do is we want to make this little table. 

00:45:00.297 --> 00:45:03.291
And you want the table, and I'm just going to just write it in right here.  

00:45:03.293 --> 00:45:10.794
You want the sine, the cosine, and the tangent, and this needs to go in here, 

00:45:10.793 --> 00:45:19.047
of 30 degrees, 45 degrees, and 60 degrees. And this is something you want to write

00:45:19.049 --> 00:45:25.823
down over and over and over and over again until you are just totally 

00:45:25.825 --> 00:45:34.581
comfortable with it. OK, so what do we have? We have the sine of 30.  

00:45:34.583 --> 00:45:44.582
Now that's this batch right here. So we have the sine of 30 is 1/2, the cosine of 30

00:45:44.584 --> 00:45:52.331
is the square root of 3 over 2, and the tangent of 30 is 1 over the square root of 3.

00:45:52.333 --> 00:46:00.106
OK, next column would be these. The sine and cosine are the same.  

00:46:00.108 --> 00:46:04.361
You see how easy this is to memorize. You just get comfortable with it. 

00:46:04.363 --> 00:46:17.863
And then the tangent of 45 is 1, and then we have this last batch.  

00:46:17.865 --> 00:46:25.885
And so we have the sine of 60, which of course is the cosine of 30, 

00:46:25.887 --> 00:46:31.866
so these are easy. They're just switched, and then this one is the reciprocal.  

00:46:31.868 --> 00:46:45.635
This right here is so important. You will use it over and over and over again.  

00:46:45.637 --> 00:46:49.384
Let's take a look at some examples where we use this information.  

00:46:50.402 --> 00:46:58.902
Example 1: Find the exact value of each expression. Notice that what we have here

00:46:58.904 --> 00:47:04.922
are all trig functions of acute angles, but not only that. All of these acute angles

00:47:04.924 --> 00:47:09.928
are special angles. Below I have the table that we generated by drawing 

00:47:09.930 --> 00:47:16.685
the triangles for 45, 30, and 60 degrees. And finding the trig functions from there

00:47:16.687 --> 00:47:19.690
you can of course use the triangles or you can use this table.

00:47:19.692 --> 00:47:27.190
Alright, so let's see what we have. The sine of 45 degrees. OK, the sine of 45 degrees

00:47:27.192 --> 00:47:34.956
is 1 over the square root of 2. We want to multiply that by the cosine of 30 degrees.

00:47:34.956 --> 00:47:42.961
The cosine of 30 degrees is the square root of 3 over 2.  

00:47:42.961 --> 00:47:50.900
Now what we're really doing here is practicing using this information. So we're going

00:47:50.902 --> 00:47:58.718
to multiply here, and we will get the square root of 3 over 2 square root of 2.  

00:47:58.720 --> 00:48:02.970
Let me point out right here to you something about rationalizing.  

00:48:02.972 --> 00:48:07.731
The sine and the cosine in particular say of 45 degrees

00:48:07.733 --> 00:48:09.237
are 1 over the square root of 2. 

00:48:09.239 --> 00:48:14.495
You don't have to rationalize, but if you chose to do so, you would multiply 

00:48:14.497 --> 00:48:18.995
this expression by the square root of 2 over the square root of 2 

00:48:18.997 --> 00:48:23.751
which would then simplify and you'd get the square root of 2 over 2.  

00:48:23.753 --> 00:48:28.503
What you want to do is recognize that if you ever see this expression 

00:48:28.505 --> 00:48:34.002
it is equivalent to 1 over the square root of 2 and also to this one.  

00:48:34.004 --> 00:48:38.771
The same thing for this. This is actually equivalent to the square root of 3 over 3,

00:48:38.773 --> 00:48:42.769
and so you may see that at some point too. Alright, let's go to b.  

00:48:42.771 --> 00:48:49.516
The tangent of pi over 4. Ok well the tangent of pi over 4 is 1, 

00:48:49.518 --> 00:48:57.285
and the sine of pi over 3 which is 60 degrees is the square root of 3 over 2.  

00:48:57.287 --> 00:49:01.036
Now how can we simplify this? Well, we can get a common denominator,

00:49:01.038 --> 00:49:08.288
so we write 1 as 2 over 2 and then subtract the square root of 3 over 2.  

00:49:08.290 --> 00:49:20.035
We can combine the terms in the numerator, over the denominator.  

00:49:20.037 --> 00:49:26.067
Let's look at the third one. The tangent squared of pi over 6.

00:49:26.069 --> 00:49:34.317
Well the tangent of pi over 6 is 1 over the square root of 3, and what we want to do is 

00:49:34.319 --> 00:49:41.817
from here we want to square this. Then we want to add sine squared of pi over 4.

00:49:41.817 --> 00:49:52.593
So the sine of pi over 4 is 1 over the square root of 2. Don't forget to square it.

00:49:52.595 --> 00:50:02.592
And what do we get? This would be 1 over 3 plus 1 over 2, common denominator, 

00:50:02.594 --> 00:50:11.613
this would be 2/6, 3/6, exact value 5/6.

00:50:11.615 --> 00:50:16.863
Alright, so what you need to do is memorize the trig functions of the three

00:50:16.865 --> 00:50:21.868
special angles and be able to use them quickly and efficiently.

00:50:21.870 --> 00:50:26.377
But what happens if your acute angle is not one of those three special angles?

00:50:26.379 --> 00:50:31.130
Then you need to use a calculator. Let's take an example of that 

00:50:31.132 --> 00:50:35.130
and work out some exercises using the calculator. 

00:50:36.636 --> 00:50:43.637
Example 2: Find the value correct to two decimal places. Notice that these 

00:50:43.639 --> 00:50:48.150
are all trig functions of acute angles, but none of these are special angles, and so

00:50:48.152 --> 00:50:51.650
we're not going to be able to read off the triangle or the table that we've memorized. 

00:50:51.652 --> 00:50:56.402
Instead we're going to have to look up these values that are stored in our calculator.  

00:50:56.404 --> 00:51:05.167
OK, the big thing here is units degrees, radians, degrees, radians.

00:51:05.169 --> 00:51:12.170
Your calculator must be in the correct mode in order for you to get the correct answer.  

00:51:12.172 --> 00:51:19.170
Alright so this is the sine of 48 degrees. Make sure your calculator is in degrees.  

00:51:19.172 --> 00:51:24.686
The default is usually degrees, but you should always check that. So I'm in degrees,

00:51:24.688 --> 00:51:29.184
and now I want the sine of 48 degrees. Now depending on what kind of calculator 

00:51:29.186 --> 00:51:32.940
you have you may have to enter this, if you have sort of an old fashioned

00:51:32.941 --> 00:51:37.945
scientific calculator you may have to put the angle in first and then the trig function.  

00:51:37.947 --> 00:51:40.946
If you get one that has a display, which is what I would recommend 

00:51:40.948 --> 00:51:47.207
it's much easier to work with, you can depress the sine button and then you can 

00:51:47.209 --> 00:51:52.964
put in 48. It's already in degrees, enter, and out comes the answer, 

00:51:52.966 --> 00:51:59.466
and then I want to round correct to two decimal places. I get 0.743,

00:51:59.468 --> 00:52:10.463
and so when I round I get approximately decimal 74.  Alright, what unit is this?

00:52:10.465 --> 00:52:16.712
Radians. So clear your calculator and put it in radian mode.  

00:52:16.714 --> 00:52:22.242
OK, I'm bringing up radian mode, I am selecting it, and it now says radian mode.

00:52:22.244 --> 00:52:31.247
I want the cosine of pi over 12, so that's pi, and there's usually a key for pi,

00:52:31.249 --> 00:52:40.762
and then divided by 12, enter, and I get .9659 and so forth, rounded to two

00:52:40.764 --> 00:52:52.011
decimal places is going to be .96. OK, now let's see. This was 9659, so you know 

00:52:52.013 --> 00:53:00.010
when I round this it should actually be .97. Be careful when you are rounding.  

00:53:00.012 --> 00:53:10.511
OK, let's clear the calculator, and let's go back to degree mode. OK, so mode, degrees, 

00:53:10.513 --> 00:53:18.264
enter. OK, I'm in degrees, but this is the secant of 17 degrees, and if you look at 

00:53:18.266 --> 00:53:22.799
the calculator it has sine, cosine, and tangent. So how can I get the secant?  

00:53:22.801 --> 00:53:26.551
Well, that's what we learned all those identities for.  

00:53:26.553 --> 00:53:36.049
This is 1 over the cosine of 17 degrees. So let's enter that information. So it's 

00:53:36.051 --> 00:53:48.553
1 divided by the cosine of 17, I'm in degrees, enter, and I get 1.045 blah blah, so

00:53:48.555 --> 00:53:52.832
this is going to have to be approximate because I'm rounding, and I'm going to get 

00:53:52.834 --> 00:54:00.800
1 point 0 and I have 4 5, so I'm going to round to 1.05.

00:54:00.802 --> 00:54:04.340
OK, what about this one?  Mode? 

00:54:04.342 --> 00:54:13.073
Correct. So clear the calculator, go back to radian mode. Radian mode, enter.

00:54:13.075 --> 00:54:18.352
The cosecant is 1 over, and I have to rewrite this in terms of either 

00:54:18.354 --> 00:54:22.106
sine, cosine or tangent. And what is it? 

00:54:22.108 --> 00:54:31.102
Mmhm. Sine of pi over 5. So I'm in radians and I'm ready. It's 1 divided by 

00:54:31.104 --> 00:54:41.876
the sine of pi divided by 5 and that is equal to 1.701, so that is going to be

00:54:41.878 --> 00:54:50.380
approximately 1.70 correct to two decimal places. And so this is the process you use

00:54:50.382 --> 00:54:55.140
to find the trig functions of acute angles when they are not special angles. 

00:54:55.142 --> 00:55:00.645
You use your calculator. If you have a special angle, either 30, 60, or 45 degrees,

00:55:00.647 --> 00:55:05.700
you should know that information by heart. Practice it until you do.













