WEBVTT

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The first step to understanding polar coordinates and polar equations is to learn how to plot polar coordinates

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on a polar plane. A polar coordinate will have two values r and theta. Theta will tell us our angle of rotation,

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and r will be a directed distance along this angle. You can see on our polar plane that we have concentric 

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circles of radius 1, 2, 3, and 4 units. Looking at our first example, r is 2, which lets me know that this point

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will be lying on the circle with the radius of 2. Our angle of rotation is 2 pi over 3. So let's start

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by drawing the angle 2 pi over 3, and now our point will be on an r - value of 2. 

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Looking at the second example, r is 4, and our angle of rotation is negative pi over 2. So this means 

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we'll be rotating pi over 2 radians, but in the negative or clockwise direction. So  angle of rotation is 

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negative pi over 2, and our point lies on an r - value of 4. What might seem a little strange is seeing the next

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example, where we have a negative value for r because in the past our convention has been that r is always

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a non-negative value because it represents the radius of a circle. However, in the polar coordinate system 

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r is now a directed distance, which means it might take on a negative value, and that just indicates a change

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in the direction. So let's see what that means, looking at this example. First we have our angle of rotation, 

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5 pi over 6. Starting here, I would be at an r - value of 0, and if I moved along this ray, I would be at an r - value

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of 1, 2, 3, or 4. Since r is negative 3, I'm going to move in the opposite direction. So starting here at 0, I would

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move 1, 2, 3 units. So I'm still lying on the circle with a radius of 3 but moving in the opposite direction. 

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In our final example, we have an r - value of negative 3, and a theta value of negative 5 pi over 6. So let's start

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with negative 5 pi over 6, which means we're rotating 5 pi over 6 radians in the negative direction. 

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Now a value of negative 3 for r means we would move 1, 2, 3 units in the negative or opposite direction. 

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Take a minute to think about another way that we might represent this same point but using a positive

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value for r. I might call this point positive 3, and then use an angle of pi over 6. This ordered pair 

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(3, pi over 6) would lie on the same spot as this last example. You can see that, unlike a rectangular 

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coordinate system, where each point can only be represented in one way, any point on the polar plane 

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can be represented in an infinite number of representations.

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As we just saw in our last example, there are different ways of representing a point on the polar plane. 

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Let's take for example the point (4, pi over 4). We could represent the same point by using an angle that's 

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coterminal to pi over 4. So if I take the angle pi over 4 and add 2 pi,  I get an angle 9 pi over 4 that is 

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coterminal to pi over 4. Therefore, the ordered pair (4, 9 pi over 4) would lie on the same spot on the 

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polar plane. I could find any other coterminal angle by continuing to add or subtract any multiple of 2 pi 

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and would still have a point that lies in the same spot on our polar plane. Another way of naming this point 

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but using a negative value for r would be to find the angle that forms a line with pi over 4. So if I take pi over 4, 

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and add pi, I find that this angle is 5 pi over 4. The ordered pair (negative 4, 5 pi over 4) would lie on the same spot.

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5 pi over 4 would rotate to here, and then a value of negative 4 would move 4 units in the opposite direction.

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So in this way we're able to represent any point in an infinite number of ways. Let's look at an example. 

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We're asked to name three different representations of the point (2, 2 pi over 3). You may recall this is the 

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first point that we plotted in the earlier examples. In our example the first one that we're asked to find, we're

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asked to represent it using a value of r that is positive but a value of theta that lies between negative 2 pi and 0.

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To do that I need to find an angle that's coterminal to 2 pi over 3 but has a negative value. We take 2 pi over 3

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and subtract 2 pi. We get negative 4 pi over 3. So negative 4 pi over 3 is greater than or equal to negative 2 pi,

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and less than 0, and is coterminal to 2 pi over 3. So we can represent this point as (2, - 4 pi over 3). 

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Taking a look at the next example notice that we're now asked to represent this point using a negative value

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for r, which means that I need to find the angle that forms a line with 2 pi over 3. To do that, I'm going to 

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take 2 pi over 3 and add pi. Notice that I still want my angle to lie between 0 and 2 pi. If I take 2 pi over 3 

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and add pi, I get the angle 5 pi over 3. I can represent this point as (negative 2, 5 pi over 3). My angle 5 pi over 3 is here. 

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A value of negative 2 would move two units in the opposite direction. Finally we're asked to find a third 

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representation, where we have a positive value for r but now a value of theta that is greater than or equal to

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2 pi but less than 4 pi. So I need to find the angle that's coterminal to 2 pi over 3 but that lies between 

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2 pi and 4 pi. If I take 2 pi over 3 and add 2 pi, I get an angle of 8 pi over 3. So the third way that we can 

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represent this point is (2, 8 pi over 3).  Now as we said, there are infinitely many ways that we can represent

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this point, but all four of these representations would result in the same point on our polar plane.

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In order to convert from polar coordinates to rectangular coordinates, we need formulas that help us relate

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r and theta to x and y. Luckily we already know these formulas from previous sections. So look at point P, 

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that's r and theta. If we think about this in terms of a right triangle, we have sides x, y, and r. We know that 

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sine theta is equal to y over r. If we take this formula and rearrange it to solve for y, we get y equals r sine theta.

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We also know that cosine of theta is equal to x over r. Rearranging this formula to solve for x, we see that 

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x is equal to r cosine theta. So these are the two formulas that we will be using to convert from a  

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polar coordinate to a rectangular coordinate. You should realize that they are not new formulas to you.  

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They're just rearranged into a new form that's more useful for what we're doing here. Looking at our first example,

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we have the polar coordinate (3, 2 pi over 3), which would be in the second quadrant. You can think about it 

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as being right here. Picture taking a rectangular coordinate plane and lying it on top of our polar plane.

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We want to find to find the corresponding point (x, y) that would be in that same location. To find x, we can 

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use the formula x equals r cosine theta. In this case r is 3, and theta is 2 pi over 3. Thinking about cosine of 

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2 pi over 3, we see that it has a reference angle of pi over 3. The angle lies in quadrant two where cosine is 

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negative, so the cosine of 2 pi over 3 is negative 1/2. Our x-coordinate is negative 3/2. To find the y - value

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for our ordered pair, we use the formula y equals r sine theta. So y is equal to 3 sine of 2 pi over 3. 

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Again a reference angle of pi over 3, quadrant two where sine is positive, so the sine of 2 pi over 3 is 

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square root of 3 over 2, and so our y - value is 3 square root of 3, over 2. Our rectangular coordinate is 

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(- 3/2, 3 square root of 3 over 2). It's always good to check to see that these two points would lie in the same

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quadrant. We already established that this point is in quadrant two. Looking at your rectangular coordinate, 

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we have a negative value for x, and a positive value for y so this point in rectangular form

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also lies in quadrant two. Looking at the second example, (7, pi), we could use these formulas in the same way

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that I did in the first example. Feel free to do that if you're more comfortable with that. However, since

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the point lies on the x-axis, I can probably figure out the rectangular coordinate even without using the formulas.

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Let's look at our polar coordinate. Pi means that we would lie on the negative x-axis at an r-value of 7.

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So we would rotate over to pi, and we would move 7 units to the left. So thinking about this in terms of an x - y axis,

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if I move 7 units to the left then x would be negative 7, and since I'm on the x - axis the y - value is 0. 

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Now again while you can do this without using the formulas, you could also fill into the formulas just like

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we did in the first example. In our third example, the first thing I see is that I have a negative value for r,

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and a negative value for theta. While I could just take these and substitute them into the formula as they are,

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one way that we might make this easier is to rename this using a different representation as we did in 

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previous examples. Let's think about where (-4, -3 pi over 4) would be. Negative 3 pi over 4

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would mean rotate 3 pi over 4 radians in the negative direction which would put me in quadrant three. 

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An r - value of negative 4 would mean that I would move 4 units in the opposite direction. 

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So I see that this point is in quadrant one. I might rename it by taking negative 3 pi over 4 and adding pi,

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which would give me pi over 4. So I would rename this point as (4, pi over 4) and use that representation to

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convert it to rectangular form. Now again if you did not do this and you used the original representation you

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still should get the same answer, but it's just a more complicated problem to figure out. So filling in to our

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formulas, x is equal to r times the cosine of theta and y is equal to r times the sine of theta. 

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The cosine of pi over 4 is 1 over square root of 2, and the sine of pi over 4 is also 1 over square root of 2.

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So our coordinate will be (4 over the square root of 2, 4 over the square root of 2).

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Now that we've converted from polar to rectangular coordinates, we're going to take a look at converting

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from rectangular to polar. These first two examples are points that lie on the x - or y - axis. When that's the case,

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you don't need a formula to make the conversion. You just need to plot the point and look at where it's located.

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So let's look at our first point, (0, -1). Keep in mind that we're looking at a rectangular coordinate,

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so values x and y. To convert it we're looking for values r and theta. So looking at this as our x - y axis,

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the point (0, negative 1) would be right here on the negative y - axis. Thinking about that in terms of a polar coordinate, 

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let's think about the values of r and theta. If I start at 0, and rotate in the positive or counterclockwise

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direction, theta is 3 pi over 2. Now if you think about our polar plane with concentric circles, it would lie on

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a circle with a radius of 1 unit. So our polar coordinate would be (1, 3 pi over 2). Looking at our second example,

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(4, 0) lies on the positive x - axis, so here's our point (4, 0). Now we need to find r and theta. Since 

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our point lies on the positive x-axis, theta is 0 radians. Then if you think about our circles, this point 

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would lie on a circle with a radius of 4 units. So in polar form, this point would be (4, 0). Now this might 

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seem strange because the rectangular form looks the same as the polar form. It's important 

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to remember that this (4, 0) representing x and y doesn't have the same meaning that this (4, 0) has where 

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it represents r and theta. You also may be thinking about the fact that there are different ways that we could

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represent any of these points. You might have thought that it was (4, 2 pi), which would be a correct 

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representation, but the convention is that the directions will specify in most cases that you want an r-value

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that's positive, and a theta value that's greater than or equal to 0 but less than 2 pi. So while there are

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infinitely many representations for these points, you will generally be asked to find this particular representation.

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In our third example of converting a rectangular coordinate to polar coordinate, we now have a point that 

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does not lie on the x - or y -axis. So we're going to need some formulas that help us relate x and y to r and theta.

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Looking at our point (x, y), we want to figure out theta our angle of rotation and r the length of the segment.

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Drawing in our right triangle, we know x and y, and we can find r by using the Pythagorean theorem. 

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x squared plus y squared equals r squared. Since we're looking for r, we might go ahead and take the square

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root of both sides and write our formula as r equals the square root of x squared plus y squared. This is

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the formula that we will use when converting from rectangular to polar to find r. In this example, 

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x is negative 6 square root of 3, and y is negative 6. When squaring negative 6 square root of 3, remember 

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that both the negative 6 and the square root of 3 need to be squared. We have negative 6 squared, times 

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the square root of 3 squared. Negative 6 squared is 36, the square root of 3 squared is 3, so multiplying 

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36 times 3 we get 108 plus negative 6 squared which is 36. We now have that r is equal to the square root 

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of 144, and so r is 12. Now we need to find theta. So again recall from earlier sections how can we relate 

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theta to x and y. If you think through your trigonometric functions, we would want to use the tangent function.

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So the formula that we will use to find theta is tan theta equals y over x. Substituting in y and x into our 

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formula, we have tan theta equals negative 6 over negative 6 square root of 3, which reduces to positive 

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1 over square root of 3. Now we need to solve this trigonometric equation. To do that, we need to find the 

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reference angle. To find the reference angle, we're going to need to find the inverse tangent of the absolute 

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value of 1 over square root of 3. In this case it happens to be positive already, but recall that in a case where 

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this is a negative value, you would find the inverse tangent of the positive value. So to find theta r, we will 

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find the inverse tangent of 1 over square root of 3, and that tells me that my reference angle is pi over 6. 

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Looking at our coordinate, I see that my angle needs to be an angle that lies in the third quadrant, so I need

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to take my reference angle theta r, which I now know is pi over 6, and add pi to it. Theta will be pi plus 

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pi over 6, which is 7 pi over 6. Now we have our polar coordinates. r is 12 and theta is 7 pi over 6. 

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As a preparation for graphing equations in polar form, we're going to look at how to convert an equation 

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from rectangular form to polar form. To do that, we'll use the same four formulas that we've used earlier in 

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this section. In our rectangular equation, the equation will be in terms of x or y or both, and we will need 

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to rewrite it to be in terms of r or theta or both. In the first example, our equation is x squared plus y squared

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equals 49. Looking at our formulas, I see that x squared plus y squared is equal to r squared. Therefore

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I can replace x squared plus y squared with r squared, and rewrite the equation as r squared equals 49. 

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Taking the square root of both sides, I get two possible equations. r equals 7 or r equals negative 7. 

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Either of these is an acceptable polar form for this rectangular equation. In the second example, I again want

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to replace this, the x's and y's so that they're in terms of r or theta or both. To do this I'm first going to take

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the x minus 1 squared and expand it by multiplying x minus 1 times x minus 1. That gives me x squared

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minus 2x plus 1, plus y squared equals 1. Rearranging my terms on the left hand side, I can write x squared

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plus y squared minus 2x, and then if I subtract 1 from both sides, it's now equal to 0. Again x squared plus

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y squared is equal to r squared, so I can replace x squared plus y squared with r squared. I see that x is equal

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to r cosine theta, so I can replace the x with r cosine theta. I now have a polar equation because it's in terms 

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of r and theta. However the convention for a polar equation is generally to write it in terms of r equals. So

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I would like to take this equation and solve for r. To do that I'm going to factor out the common factor of r, 

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so I have r times r minus 2 cosine theta equals 0. Setting each of these factors equal to 0, I get two possible

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equations. r equals 0 or r minus 2 cosine theta equals 0, which gives me r equals 2 cosine theta. 

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The equation r equals 0 is not necessary to include because r equals 2 cosine theta also includes the r - values

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of 0. So the only equation that we need to express this in polar form is r equals 2 cosine theta, and so that is

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the polar form of this rectangular equation. In the final example, we have the rectangular equation x equals 9.

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Again using the fact that x is equal to r cosine theta, I can replace x with r cosine theta. Solving the equation 

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for r, by dividing both sides by cosine theta, I get that r is equal to 9 over cosine theta, which can be written 

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that way or using one of our reciprocal identities. I could rewrite this as r equals 9 times secant theta.

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So when converting from rectangular to polar form in a equation, you need to use the formulas that we 

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know that relate x and y to r and theta to rewrite the equation to be in terms of r or theta or both.

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Now that we've converted equations from rectangular to polar form, we're going to look at how we can use 

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those same four formulas to convert from polar to rectangular form. So now we have equations that are in 

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terms of r or theta or both, and we want to rewrite them to be in terms of x or y or both. Looking at the 

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first example, I have r equals 5. Scanning the formulas I see that if I had r squared, I could use the third 

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formula. x squared plus y squared equals r squared. So I want to take my equation and square both sides 

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and rewrite it as r squared equals 25. Now I can replace the r squared with x squared plus y squared, and 

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my rectangular form of the equation will be x squared plus y squared equals 25. Looking at the second 

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example, it might make sense at first glance to maybe square both sides again. However if you look at the 

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right - hand side, if we square this side we would then have sine squared theta. If you look at your formulas 

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you see that we don't really have a formula that we could immediately use if we had sine squared. Instead

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we're going to try a little bit different tactic. We're going to take this equation and we're going to

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multiply both sides by r. So if I have r equals negative 5 sine theta, and I multiply both sides by r, I see that

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I have r squared equals negative 5 r sine theta. Now I can again replace r squared with x squared plus 

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y squared, and then on the right hand side I can replace r sine theta with y. 

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I've now written my equation to where each side is in terms of x or y or both. 

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In the third example, I see that it looks very similar to example two. So again I might think that multiplying

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both sides by r would be a good tactic. But again if you look at the right hand side, it is now in terms of 

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cosecant and we only have formulas that help us relate cosine, sine, or tangent functions to x and y. 

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What we're going to do instead is first use the reciprocal identitiy for cosecant, and rewrite cosecant as 

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1 over sine theta. Multiplying both sides by sine theta, we have r sine theta equals negative 5. Now I can 

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replace r sine theta with y, and the rectangular form of my equation is y equals negative 5. 

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So when converting from polar to rectangular form, you'll often have to manipulate the equation so that 

00:32:00.103  --> 00:32:08.350
it matches one of your four formulas in order to be able to make a substitution.
































